What are the solutions to the equation solvefor y,y^2=x^3(2-x) ?

The solutions to the equation solvefor y,y^2=x^3(2-x) are y=xsqrt(x)sqrt(2-x),y=-xsqrt(x)sqrt(2-x)

Find the zeros of solvefor y,y^2=x^3(2-x)

The zeros of solvefor y,y^2=x^3(2-x) are y=xsqrt(x)sqrt(2-x),y=-xsqrt(x)sqrt(2-x)

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solve for

y, y^{2} = x^{3} (2 - x)

y = x x 2 - x, y = - x x 2 - x

Solution steps

y^{2} = x^{3} (2 - x)

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = x^{3} (2 - x), y = - x^{3} (2 - x)

Simplify

x^{3} (2 - x) : x x 2 - x

Simplify

- x^{3} (2 - x) : - x x 2 - x

y = x x 2 - x, y = - x x 2 - x

4 x^{2} - 9 x + 20 = 0

12 x^{2} - x = 6

\frac{9}{169} + \frac{y ^{2}}{100} = 1

c^{2} = 5^{2} - 3^{2}

x, x^{2} - 3 = 0

What are the solutions to the equation solvefor y,y^2=x^3(2-x) ?
The solutions to the equation solvefor y,y^2=x^3(2-x) are y=xsqrt(x)sqrt(2-x),y=-xsqrt(x)sqrt(2-x)
Find the zeros of solvefor y,y^2=x^3(2-x)
The zeros of solvefor y,y^2=x^3(2-x) are y=xsqrt(x)sqrt(2-x),y=-xsqrt(x)sqrt(2-x)