What are the solutions to the equation -x^2-4=14 ?

The solutions to the equation -x^2-4=14 are x=sqrt(2)*3i,x=-sqrt(2)*3i

Find the zeros of -x^2-4=14

The zeros of -x^2-4=14 are x=sqrt(2)*3i,x=-sqrt(2)*3i

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- x^{2} - 4 = 14

x = 2 \cdot 3 i, x = - 2 \cdot 3 i

Solution steps

- x^{2} - 4 = 14

Move

4

to the right side

- x^{2} = 18

Divide both sides by

- 1

x^{2} = - 18

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 18, x = - - 18

- 18 = 2 \cdot 3 i

- - 18 = - 2 \cdot 3 i

x = 2 \cdot 3 i, x = - 2 \cdot 3 i

2 b^{2} = 32

3 x^{2} + 1 x = 0

x^{2} + 5 x - 6 = 0

2^{2} + b^{2} = 1 1^{2}

y, x y - 1 = x + y^{2}

What are the solutions to the equation -x^2-4=14 ?
The solutions to the equation -x^2-4=14 are x=sqrt(2)*3i,x=-sqrt(2)*3i
Find the zeros of -x^2-4=14
The zeros of -x^2-4=14 are x=sqrt(2)*3i,x=-sqrt(2)*3i