What are the solutions to the equation 12a^2-7a=12 ?

The solutions to the equation 12a^2-7a=12 are a= 4/3 ,a=-3/4

Find the zeros of 12a^2-7a=12

The zeros of 12a^2-7a=12 are a= 4/3 ,a=-3/4

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12 a^{2} - 7 a = 12

a = \frac{4}{3}, a = - \frac{3}{4}

Decimal Notation

a = 1.33333 \dots, a = - 0.75

Solution steps

12 a^{2} - 7 a = 12

Move

12

to the left side

12 a^{2} - 7 a - 12 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 12 ( - 12 )}{2 \cdot 12}

(- 7)^{2} - 4 \cdot 12 (- 12) = 25

a_{1, 2} = \frac{- ( - 7 ) \pm 25}{2 \cdot 12}

Separate the solutions

a_{1} = \frac{- ( - 7 ) + 25}{2 \cdot 12}, a_{2} = \frac{- ( - 7 ) - 25}{2 \cdot 12}

a = \frac{- ( - 7 ) + 25}{2 \cdot 12} : \frac{4}{3}

a = \frac{- ( - 7 ) - 25}{2 \cdot 12} : - \frac{3}{4}

The solutions to the quadratic equation are:

a = \frac{4}{3}, a = - \frac{3}{4}

4 x^{2} + 64 x = 0

36 s^{2} - 12 s + 1 = 0

4 = - 16 t^{2} + 32 t + 6

x, x^{2} + y^{2} - z^{2} = 4

x, (y - x)^{2} + (z - x)^{2} = (y + x)^{2}

What are the solutions to the equation 12a^2-7a=12 ?
The solutions to the equation 12a^2-7a=12 are a= 4/3 ,a=-3/4
Find the zeros of 12a^2-7a=12
The zeros of 12a^2-7a=12 are a= 4/3 ,a=-3/4