What are the solutions to the equation 9x^2-72=-18x ?

The solutions to the equation 9x^2-72=-18x are x=2,x=-4

Find the zeros of 9x^2-72=-18x

The zeros of 9x^2-72=-18x are x=2,x=-4

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9 x^{2} - 72 = - 18 x

x = 2, x = - 4

Solution steps

9 x^{2} - 72 = - 18 x

Move

18 x

to the left side

9 x^{2} - 72 + 18 x = 0

Write in the standard form

a x^{2} + b x + c = 0

9 x^{2} + 18 x - 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 9 ( - 72 )}{2 \cdot 9}

1 8^{2} - 4 \cdot 9 (- 72) = 54

x_{1, 2} = \frac{- 18 \pm 54}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 18 + 54}{2 \cdot 9}, x_{2} = \frac{- 18 - 54}{2 \cdot 9}

x = \frac{- 18 + 54}{2 \cdot 9} : 2

x = \frac{- 18 - 54}{2 \cdot 9} : - 4

The solutions to the quadratic equation are:

x = 2, x = - 4

19 y^{2} - 13 y + 2 = y^{2}

x^{2} + 2 x - 11 = 4

8 x^{2} - 5 = 0

25 x^{2} + 100 = 0

3 x^{2} = 9 x + 4

What are the solutions to the equation 9x^2-72=-18x ?
The solutions to the equation 9x^2-72=-18x are x=2,x=-4
Find the zeros of 9x^2-72=-18x
The zeros of 9x^2-72=-18x are x=2,x=-4