What are the solutions to the equation x^2-10x=26 ?

The solutions to the equation x^2-10x=26 are x=5+sqrt(51),x=5-sqrt(51)

Find the zeros of x^2-10x=26

The zeros of x^2-10x=26 are x=5+sqrt(51),x=5-sqrt(51)

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x^{2} - 10 x = 26

x = 5 + 51, x = 5 - 51

Decimal Notation

x = 12.14142 \dots, x = - 2.14142 \dots

Solution steps

x^{2} - 10 x = 26

Move

26

to the left side

x^{2} - 10 x - 26 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot ( - 26 )}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot (- 26) = 251

x_{1, 2} = \frac{- ( - 10 ) \pm 2 51}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 51}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 2 51}{2 \cdot 1}

x = \frac{- ( - 10 ) + 2 51}{2 \cdot 1} : 5 + 51

x = \frac{- ( - 10 ) - 2 51}{2 \cdot 1} : 5 - 51

The solutions to the quadratic equation are:

x = 5 + 51, x = 5 - 51

1 + 2 + n = \frac{n ( n + 1 )}{2}

5 x^{2} + 8 x - 15 = 0

x, y^{(3)} = 8 x^{2} + 1

6 x^{2} + 6 x - 252 = 0

(3 - x)^{2} - 16 = 0

What are the solutions to the equation x^2-10x=26 ?
The solutions to the equation x^2-10x=26 are x=5+sqrt(51),x=5-sqrt(51)
Find the zeros of x^2-10x=26
The zeros of x^2-10x=26 are x=5+sqrt(51),x=5-sqrt(51)