What are the solutions to the equation 6x^2+6x-252=0 ?

The solutions to the equation 6x^2+6x-252=0 are x=6,x=-7

Find the zeros of 6x^2+6x-252=0

The zeros of 6x^2+6x-252=0 are x=6,x=-7

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6 x^{2} + 6 x - 252 = 0

x = 6, x = - 7

Solution steps

6 x^{2} + 6 x - 252 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 6 ( - 252 )}{2 \cdot 6}

6^{2} - 4 \cdot 6 (- 252) = 78

x_{1, 2} = \frac{- 6 \pm 78}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 6 + 78}{2 \cdot 6}, x_{2} = \frac{- 6 - 78}{2 \cdot 6}

x = \frac{- 6 + 78}{2 \cdot 6} : 6

x = \frac{- 6 - 78}{2 \cdot 6} : - 7

The solutions to the quadratic equation are:

x = 6, x = - 7

(3 - x)^{2} - 16 = 0

3 x^{2} - 222 x + 845 = 0

0 = - 2 x^{2} - 4 x - 1

x^{2} = 30 0^{2} + 40 0^{2}

lo g_{10} (5) (x^{2} + 10 x + 1) = 2

What are the solutions to the equation 6x^2+6x-252=0 ?
The solutions to the equation 6x^2+6x-252=0 are x=6,x=-7
Find the zeros of 6x^2+6x-252=0
The zeros of 6x^2+6x-252=0 are x=6,x=-7