What are the solutions to the equation 0=-2x^2-4x-1 ?

The solutions to the equation 0=-2x^2-4x-1 are x=-(2+sqrt(2))/2 ,x=-(2-sqrt(2))/2

Find the zeros of 0=-2x^2-4x-1

The zeros of 0=-2x^2-4x-1 are x=-(2+sqrt(2))/2 ,x=-(2-sqrt(2))/2

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0 = - 2 x^{2} - 4 x - 1

x = - \frac{2 + 2}{2}, x = - \frac{2 - 2}{2}

Decimal Notation

x = - 1.70710 \dots, x = - 0.29289 \dots

Solution steps

0 = - 2 x^{2} - 4 x - 1

Switch sides

- 2 x^{2} - 4 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 2 ) ( - 1 )}{2 ( - 2 )}

(- 4)^{2} - 4 (- 2) (- 1) = 22

x_{1, 2} = \frac{- ( - 4 ) \pm 2 2}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 2}{2 ( - 2 )}, x_{2} = \frac{- ( - 4 ) - 2 2}{2 ( - 2 )}

x = \frac{- ( - 4 ) + 2 2}{2 ( - 2 )} : - \frac{2 + 2}{2}

x = \frac{- ( - 4 ) - 2 2}{2 ( - 2 )} : - \frac{2 - 2}{2}

The solutions to the quadratic equation are:

x = - \frac{2 + 2}{2}, x = - \frac{2 - 2}{2}

x^{2} = 30 0^{2} + 40 0^{2}

lo g_{10} (5) (x^{2} + 10 x + 1) = 2

x^{2} + 20 = 9 x

2 x^{2} + 8 x + 11

x^{2} + 4 = 16

What are the solutions to the equation 0=-2x^2-4x-1 ?
The solutions to the equation 0=-2x^2-4x-1 are x=-(2+sqrt(2))/2 ,x=-(2-sqrt(2))/2
Find the zeros of 0=-2x^2-4x-1
The zeros of 0=-2x^2-4x-1 are x=-(2+sqrt(2))/2 ,x=-(2-sqrt(2))/2