What are the solutions to the equation x^2+20=9x ?

The solutions to the equation x^2+20=9x are x=5,x=4

Find the zeros of x^2+20=9x

The zeros of x^2+20=9x are x=5,x=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 20 = 9 x

x = 5, x = 4

Solution steps

x^{2} + 20 = 9 x

Move

9 x

to the left side

x^{2} + 20 - 9 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 9 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 20 = 1

x_{1, 2} = \frac{- ( - 9 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 1}{2 \cdot 1}

x = \frac{- ( - 9 ) + 1}{2 \cdot 1} : 5

x = \frac{- ( - 9 ) - 1}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

x = 5, x = 4

2 x^{2} + 8 x + 11

x^{2} + 4 = 16

3 x^{2} - 36 x + 105 = 0

k^{2} + 2 k + 2 = 0

3 x^{2} + b x + c = 0

What are the solutions to the equation x^2+20=9x ?
The solutions to the equation x^2+20=9x are x=5,x=4
Find the zeros of x^2+20=9x
The zeros of x^2+20=9x are x=5,x=4