What are the solutions to the equation 3x^2-36x+105=0 ?

The solutions to the equation 3x^2-36x+105=0 are x=7,x=5

Find the zeros of 3x^2-36x+105=0

The zeros of 3x^2-36x+105=0 are x=7,x=5

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3 x^{2} - 36 x + 105 = 0

x = 7, x = 5

Solution steps

3 x^{2} - 36 x + 105 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 3 \cdot 105}{2 \cdot 3}

(- 36)^{2} - 4 \cdot 3 \cdot 105 = 6

x_{1, 2} = \frac{- ( - 36 ) \pm 6}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 36 ) + 6}{2 \cdot 3}, x_{2} = \frac{- ( - 36 ) - 6}{2 \cdot 3}

x = \frac{- ( - 36 ) + 6}{2 \cdot 3} : 7

x = \frac{- ( - 36 ) - 6}{2 \cdot 3} : 5

The solutions to the quadratic equation are:

x = 7, x = 5

k^{2} + 2 k + 2 = 0

3 x^{2} + b x + c = 0

- x + 2 = x^{2} - 2

5 v^{2} + 10 v = 0

v, e = \frac{m v ^{2}}{2} + m g h

What are the solutions to the equation 3x^2-36x+105=0 ?
The solutions to the equation 3x^2-36x+105=0 are x=7,x=5
Find the zeros of 3x^2-36x+105=0
The zeros of 3x^2-36x+105=0 are x=7,x=5