What are the solutions to the equation k^2+2k+2=0 ?

The solutions to the equation k^2+2k+2=0 are k=-1+i,k=-1-i

Find the zeros of k^2+2k+2=0

The zeros of k^2+2k+2=0 are k=-1+i,k=-1-i

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k^{2} + 2 k + 2 = 0

k = - 1 + i, k = - 1 - i

Solution steps

k^{2} + 2 k + 2 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 2 : 2 i

k_{1, 2} = \frac{- 2 \pm 2 i}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- 2 + 2 i}{2 \cdot 1}, k_{2} = \frac{- 2 - 2 i}{2 \cdot 1}

k = \frac{- 2 + 2 i}{2 \cdot 1} : - 1 + i

k = \frac{- 2 - 2 i}{2 \cdot 1} : - 1 - i

The solutions to the quadratic equation are:

k = - 1 + i, k = - 1 - i

3 x^{2} + b x + c = 0

- x + 2 = x^{2} - 2

5 v^{2} + 10 v = 0

v, e = \frac{m v ^{2}}{2} + m g h

7 x^{2} + 9 x - 148 = 0

What are the solutions to the equation k^2+2k+2=0 ?
The solutions to the equation k^2+2k+2=0 are k=-1+i,k=-1-i
Find the zeros of k^2+2k+2=0
The zeros of k^2+2k+2=0 are k=-1+i,k=-1-i