What are the solutions to the equation 7x^2+9x-148=0 ?

The solutions to the equation 7x^2+9x-148=0 are x=4,x=-37/7

Find the zeros of 7x^2+9x-148=0

The zeros of 7x^2+9x-148=0 are x=4,x=-37/7

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7 x^{2} + 9 x - 148 = 0

x = 4, x = - \frac{37}{7}

Decimal Notation

x = 4, x = - 5.28571 \dots

Solution steps

7 x^{2} + 9 x - 148 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 7 ( - 148 )}{2 \cdot 7}

9^{2} - 4 \cdot 7 (- 148) = 65

x_{1, 2} = \frac{- 9 \pm 65}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 9 + 65}{2 \cdot 7}, x_{2} = \frac{- 9 - 65}{2 \cdot 7}

x = \frac{- 9 + 65}{2 \cdot 7} : 4

x = \frac{- 9 - 65}{2 \cdot 7} : - \frac{37}{7}

The solutions to the quadratic equation are:

x = 4, x = - \frac{37}{7}

x, (5 x + y)^{2} + 9 x - 2 y = 4 x (- 8 y + 3)^{3}

(x - 3)^{2} - 9 = - x

10 x (x - 2) = 45 x [\frac{x}{5} - \frac{1}{9}]

18 x^{2} - 18 x - 108 = 0

4 x^{2} - 30 = 2

What are the solutions to the equation 7x^2+9x-148=0 ?
The solutions to the equation 7x^2+9x-148=0 are x=4,x=-37/7
Find the zeros of 7x^2+9x-148=0
The zeros of 7x^2+9x-148=0 are x=4,x=-37/7