What are the solutions to the equation 6a^2+10=60+4a^2 ?

The solutions to the equation 6a^2+10=60+4a^2 are a=5,a=-5

Find the zeros of 6a^2+10=60+4a^2

The zeros of 6a^2+10=60+4a^2 are a=5,a=-5

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6 a^{2} + 10 = 60 + 4 a^{2}

a = 5, a = - 5

Solution steps

6 a^{2} + 10 = 60 + 4 a^{2}

Move

10

to the right side

6 a^{2} = 4 a^{2} + 50

Move

4 a^{2}

to the left side

2 a^{2} = 50

Divide both sides by

2

a^{2} = 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = 25, a = - 25

25 = 5

- 25 = - 5

a = 5, a = - 5

x^{2} + 2 x - 15 = 0

(s + 4)^{2} = 0

(x - 4)^{2} + (x - 3)^{2} = 25

V = \frac{0.005}{2} (1000) (6.5 - V - 0.5)^{2}

12 = 2 \cdot 3 \cdot x^{2}

What are the solutions to the equation 6a^2+10=60+4a^2 ?
The solutions to the equation 6a^2+10=60+4a^2 are a=5,a=-5
Find the zeros of 6a^2+10=60+4a^2
The zeros of 6a^2+10=60+4a^2 are a=5,a=-5