What are the solutions to the equation 2a^2-8a=0 ?

The solutions to the equation 2a^2-8a=0 are a=4,a=0

Find the zeros of 2a^2-8a=0

The zeros of 2a^2-8a=0 are a=4,a=0

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2 a^{2} - 8 a = 0

a = 4, a = 0

Solution steps

2 a^{2} - 8 a = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 8)^{2} - 4 \cdot 2 \cdot 0 = 8

a_{1, 2} = \frac{- ( - 8 ) \pm 8}{2 \cdot 2}

Separate the solutions

a_{1} = \frac{- ( - 8 ) + 8}{2 \cdot 2}, a_{2} = \frac{- ( - 8 ) - 8}{2 \cdot 2}

a = \frac{- ( - 8 ) + 8}{2 \cdot 2} : 4

a = \frac{- ( - 8 ) - 8}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

a = 4, a = 0

- x^{2} - 2 - x = - 4 - 2 x^{2} + 5 x

2 5^{2} = x^{2} + 7^{2}

3 x^{2} - 5 x = 4 - 3 x^{2}

72 x^{2} = 8 x

x^{1} - 5 x^{2} = 0, - x^{1} + 5 x^{2} = 0

What are the solutions to the equation 2a^2-8a=0 ?
The solutions to the equation 2a^2-8a=0 are a=4,a=0
Find the zeros of 2a^2-8a=0
The zeros of 2a^2-8a=0 are a=4,a=0