What are the solutions to the equation 36x^2+96x+48=0 ?

The solutions to the equation 36x^2+96x+48=0 are x=-2/3 ,x=-2

Find the zeros of 36x^2+96x+48=0

The zeros of 36x^2+96x+48=0 are x=-2/3 ,x=-2

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36 x^{2} + 96 x + 48 = 0

x = - \frac{2}{3}, x = - 2

Decimal Notation

x = - 0.66666 \dots, x = - 2

Solution steps

36 x^{2} + 96 x + 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 96 \pm 9 6 ^{2} - 4 \cdot 36 \cdot 48}{2 \cdot 36}

9 6^{2} - 4 \cdot 36 \cdot 48 = 48

x_{1, 2} = \frac{- 96 \pm 48}{2 \cdot 36}

Separate the solutions

x_{1} = \frac{- 96 + 48}{2 \cdot 36}, x_{2} = \frac{- 96 - 48}{2 \cdot 36}

x = \frac{- 96 + 48}{2 \cdot 36} : - \frac{2}{3}

x = \frac{- 96 - 48}{2 \cdot 36} : - 2

The solutions to the quadratic equation are:

x = - \frac{2}{3}, x = - 2

12 x^{2} + 14 x - 6 = 0

- y^{2} + 6 y

x, y^{3} x + y^{2} x^{2} = 6

(x + 7)^{2} + x^{2} = 1 3^{2}

2 x^{2} - 11 x + 5 = 0

What are the solutions to the equation 36x^2+96x+48=0 ?
The solutions to the equation 36x^2+96x+48=0 are x=-2/3 ,x=-2
Find the zeros of 36x^2+96x+48=0
The zeros of 36x^2+96x+48=0 are x=-2/3 ,x=-2