What are the solutions to the equation 4x+4=-x^2 ?

The solutions to the equation 4x+4=-x^2 are x=-2

Find the zeros of 4x+4=-x^2

The zeros of 4x+4=-x^2 are x=-2

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4 x + 4 = - x^{2}

x = - 2

Solution steps

4 x + 4 = - x^{2}

Switch sides

- x^{2} = 4 x + 4

Move

4

to the left side

- x^{2} - 4 = 4 x

Move

4 x

to the left side

- x^{2} - 4 - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} - 4 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 1 ) ( - 4 )}{2 ( - 1 )}

(- 4)^{2} - 4 (- 1) (- 4) = 0

x_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 ( - 1 )}

x = \frac{- ( - 4 )}{2 ( - 1 )}

\frac{- ( - 4 )}{2 ( - 1 )} = - 2

x = - 2

The solution to the quadratic equation is:

x = - 2

x^{2} = 6 x - 14

x = x^{2} - 2 x + 1

9 x^{2} + 10 x = 5

x, - 2 x^{2} + y^{3} - 7 y + x = 0

5^{2} = a^{2} + (\frac{5}{2})^{2}

What are the solutions to the equation 4x+4=-x^2 ?
The solutions to the equation 4x+4=-x^2 are x=-2
Find the zeros of 4x+4=-x^2
The zeros of 4x+4=-x^2 are x=-2