What are the solutions to the equation 0=16t-4.9t^2 ?

The solutions to the equation 0=16t-4.9t^2 are t=0,t= 160/49

Find the zeros of 0=16t-4.9t^2

The zeros of 0=16t-4.9t^2 are t=0,t= 160/49

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = 16 t - 4.9 t^{2}

t = 0, t = \frac{160}{49}

Decimal Notation

t = 0, t = 3.26530 \dots

Solution steps

0 = 16 t - 4.9 t^{2}

Multiply both sides by

10

0 = 160 t - 49 t^{2}

Switch sides

160 t - 49 t^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 49 t^{2} + 160 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 160 \pm 16 0 ^{2} - 4 ( - 49 ) \cdot 0}{2 ( - 49 )}

16 0^{2} - 4 (- 49) \cdot 0 = 160

t_{1, 2} = \frac{- 160 \pm 160}{2 ( - 49 )}

Separate the solutions

t_{1} = \frac{- 160 + 160}{2 ( - 49 )}, t_{2} = \frac{- 160 - 160}{2 ( - 49 )}

t = \frac{- 160 + 160}{2 ( - 49 )} : 0

t = \frac{- 160 - 160}{2 ( - 49 )} : \frac{160}{49}

The solutions to the quadratic equation are:

t = 0, t = \frac{160}{49}

2 x^{2} = x - 3

z^{2} = 1 + j 3

x^{2} - 9 = 9

y^{2} + y + \frac{1}{4} = 0

(x + 6) (x + 16) = 2 (x) (x + 10)

What are the solutions to the equation 0=16t-4.9t^2 ?
The solutions to the equation 0=16t-4.9t^2 are t=0,t= 160/49
Find the zeros of 0=16t-4.9t^2
The zeros of 0=16t-4.9t^2 are t=0,t= 160/49