What are the solutions to the equation y^2+y+1/4 =0 ?

The solutions to the equation y^2+y+1/4 =0 are y=-1/2

Find the zeros of y^2+y+1/4 =0

The zeros of y^2+y+1/4 =0 are y=-1/2

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y^{2} + y + \frac{1}{4} = 0

y = - \frac{1}{2}

Decimal Notation

y = - 0.5

Solution steps

y^{2} + y + \frac{1}{4} = 0

Multiply both sides by

4

4 y^{2} + 4 y + 1 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

4^{2} - 4 \cdot 4 \cdot 1 = 0

y_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 4}

y = \frac{- 4}{2 \cdot 4}

\frac{- 4}{2 \cdot 4} = - \frac{1}{2}

y = - \frac{1}{2}

The solution to the quadratic equation is:

y = - \frac{1}{2}

(x + 6) (x + 16) = 2 (x) (x + 10)

(x + 5)^{2} = 7

(x + 4)^{2} = 15

6 - 20 x + 12 x^{2} = 0

5 x^{2} + x - 5 = 0

What are the solutions to the equation y^2+y+1/4 =0 ?
The solutions to the equation y^2+y+1/4 =0 are y=-1/2
Find the zeros of y^2+y+1/4 =0
The zeros of y^2+y+1/4 =0 are y=-1/2