What are the solutions to the equation 4y^2+60=100 ?

The solutions to the equation 4y^2+60=100 are y=sqrt(10),y=-sqrt(10)

Find the zeros of 4y^2+60=100

The zeros of 4y^2+60=100 are y=sqrt(10),y=-sqrt(10)

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4 y^{2} + 60 = 100

y = 10, y = - 10

Decimal Notation

y = 3.16227 \dots, y = - 3.16227 \dots

Solution steps

4 y^{2} + 60 = 100

Move

60

to the right side

4 y^{2} = 40

Divide both sides by

4

y^{2} = 10

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = 10, y = - 10

3 x^{2} + 2 x + 12 = - 13 x

6 x^{2} - 6 x - 5 = 0

x^{2} + 88 x = 16.64

x, x^{2} y - 3 x^{2} = 75

(3 x - 1)^{2} - (x + 5)^{2} = 0

What are the solutions to the equation 4y^2+60=100 ?
The solutions to the equation 4y^2+60=100 are y=sqrt(10),y=-sqrt(10)
Find the zeros of 4y^2+60=100
The zeros of 4y^2+60=100 are y=sqrt(10),y=-sqrt(10)