What are the solutions to the equation X^2-8X+15=0 ?

The solutions to the equation X^2-8X+15=0 are X=5,X=3

Find the zeros of X^2-8X+15=0

The zeros of X^2-8X+15=0 are X=5,X=3

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X^{2} - 8 X + 15 = 0

X = 5, X = 3

Solution steps

X^{2} - 8 X + 15 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 15 = 2

X_{1, 2} = \frac{- ( - 8 ) \pm 2}{2 \cdot 1}

Separate the solutions

X_{1} = \frac{- ( - 8 ) + 2}{2 \cdot 1}, X_{2} = \frac{- ( - 8 ) - 2}{2 \cdot 1}

X = \frac{- ( - 8 ) + 2}{2 \cdot 1} : 5

X = \frac{- ( - 8 ) - 2}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

X = 5, X = 3

(2 d + 7) (d - 3) = 0

x^{2} + 6 x - 27 = 0

5 y^{2} = - 65

(5 p + 2)^{2} = 12

12 x^{2} + 24 x - 6 = 0

What are the solutions to the equation X^2-8X+15=0 ?
The solutions to the equation X^2-8X+15=0 are X=5,X=3
Find the zeros of X^2-8X+15=0
The zeros of X^2-8X+15=0 are X=5,X=3