What are the solutions to the equation 4x^2+192x-840=0 ?

The solutions to the equation 4x^2+192x-840=0 are x=-24+sqrt(786),x=-24-sqrt(786)

Find the zeros of 4x^2+192x-840=0

The zeros of 4x^2+192x-840=0 are x=-24+sqrt(786),x=-24-sqrt(786)

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4 x^{2} + 192 x - 840 = 0

x = - 24 + 786, x = - 24 - 786

Decimal Notation

x = 4.03569 \dots, x = - 52.03569 \dots

Solution steps

4 x^{2} + 192 x - 840 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 192 \pm 19 2 ^{2} - 4 \cdot 4 ( - 840 )}{2 \cdot 4}

19 2^{2} - 4 \cdot 4 (- 840) = 8786

x_{1, 2} = \frac{- 192 \pm 8 786}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 192 + 8 786}{2 \cdot 4}, x_{2} = \frac{- 192 - 8 786}{2 \cdot 4}

x = \frac{- 192 + 8 786}{2 \cdot 4} : - 24 + 786

x = \frac{- 192 - 8 786}{2 \cdot 4} : - 24 - 786

The solutions to the quadratic equation are:

x = - 24 + 786, x = - 24 - 786

t^{2} + 7 t - 18 = 0

- 2 x^{2} + 2 = - 3 x

7 (8 x + 3) (x - 7) = 0

9 p^{2} - 24 p + 14 = 0

(y - 2) (y - 3) = 9 y + 6

What are the solutions to the equation 4x^2+192x-840=0 ?
The solutions to the equation 4x^2+192x-840=0 are x=-24+sqrt(786),x=-24-sqrt(786)
Find the zeros of 4x^2+192x-840=0
The zeros of 4x^2+192x-840=0 are x=-24+sqrt(786),x=-24-sqrt(786)