What are the solutions to the equation completesquare x^2-6x+7=0 ?

The solutions to the equation completesquare x^2-6x+7=0 are x=sqrt(2)+3,x=-sqrt(2)+3

Find the zeros of completesquare x^2-6x+7=0

The zeros of completesquare x^2-6x+7=0 are x=sqrt(2)+3,x=-sqrt(2)+3

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x^{2} - 6 x + 7 = 0

x = 2 + 3, x = - 2 + 3

Decimal Notation

x = 4.41421 \dots, x = 1.58578 \dots

Solution steps

x^{2} - 6 x + 7 = 0

Move

7

to the right side

x^{2} - 6 x = - 7

Rewrite in the form

(x + a)^{2} = b

(x - 3)^{2} = 2

For

the solutions are

f (x) = a, - a

Solve

x - 3 = 2 : x = 2 + 3

Solve

x - 3 = - 2 : x = - 2 + 3

The solutions to the quadratic equation are:

x = 2 + 3, x = - 2 + 3

x^{2} - 8 x = 12

- 2 x^{2} + 2 x + 7 = 0

x (x + 2) = e^{4}

(5 x - 1) (x + 1) = 0

x^{2} + 5 = 40

What are the solutions to the equation completesquare x^2-6x+7=0 ?
The solutions to the equation completesquare x^2-6x+7=0 are x=sqrt(2)+3,x=-sqrt(2)+3
Find the zeros of completesquare x^2-6x+7=0
The zeros of completesquare x^2-6x+7=0 are x=sqrt(2)+3,x=-sqrt(2)+3