What are the solutions to the equation 8w^2-8w-9=0 ?

The solutions to the equation 8w^2-8w-9=0 are w=(2+sqrt(22))/4 ,w=(2-sqrt(22))/4

Find the zeros of 8w^2-8w-9=0

The zeros of 8w^2-8w-9=0 are w=(2+sqrt(22))/4 ,w=(2-sqrt(22))/4

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8 w^{2} - 8 w - 9 = 0

w = \frac{2 + 22}{4}, w = \frac{2 - 22}{4}

Decimal Notation

w = 1.67260 \dots, w = - 0.67260 \dots

Solution steps

8 w^{2} - 8 w - 9 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 8 ( - 9 )}{2 \cdot 8}

(- 8)^{2} - 4 \cdot 8 (- 9) = 422

w_{1, 2} = \frac{- ( - 8 ) \pm 4 22}{2 \cdot 8}

Separate the solutions

w_{1} = \frac{- ( - 8 ) + 4 22}{2 \cdot 8}, w_{2} = \frac{- ( - 8 ) - 4 22}{2 \cdot 8}

w = \frac{- ( - 8 ) + 4 22}{2 \cdot 8} : \frac{2 + 22}{4}

w = \frac{- ( - 8 ) - 4 22}{2 \cdot 8} : \frac{2 - 22}{4}

The solutions to the quadratic equation are:

w = \frac{2 + 22}{4}, w = \frac{2 - 22}{4}

x^{2} + 16 x = - 47

x^{2} + 16 x = - 60

6 x^{2} - 12 x + 4 = 0

\frac{1}{2} y^{2} - 3 = y + 1

3 r^{2} + 30 r + 8 = 0

What are the solutions to the equation 8w^2-8w-9=0 ?
The solutions to the equation 8w^2-8w-9=0 are w=(2+sqrt(22))/4 ,w=(2-sqrt(22))/4
Find the zeros of 8w^2-8w-9=0
The zeros of 8w^2-8w-9=0 are w=(2+sqrt(22))/4 ,w=(2-sqrt(22))/4