What are the solutions to the equation (x+4)^2=2x(5x-1)-17(x-2) ?

The solutions to the equation (x+4)^2=2x(5x-1)-17(x-2) are x=1,x=2

Find the zeros of (x+4)^2=2x(5x-1)-17(x-2)

The zeros of (x+4)^2=2x(5x-1)-17(x-2) are x=1,x=2

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(x + 4)^{2} = 2 x (5 x - 1) - 17 (x - 2)

x = 1, x = 2

Solution steps

(x + 4)^{2} = 2 x (5 x - 1) - 17 (x - 2)

Expand

(x + 4)^{2} : x^{2} + 8 x + 16

Expand

2 x (5 x - 1) - 17 (x - 2) : 10 x^{2} - 19 x + 34

x^{2} + 8 x + 16 = 10 x^{2} - 19 x + 34

Move

34

to the left side

x^{2} + 8 x - 18 = 10 x^{2} - 19 x

Move

19 x

to the left side

x^{2} + 27 x - 18 = 10 x^{2}

Move

10 x^{2}

to the left side

- 9 x^{2} + 27 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 27 \pm 2 7 ^{2} - 4 ( - 9 ) ( - 18 )}{2 ( - 9 )}

2 7^{2} - 4 (- 9) (- 18) = 9

x_{1, 2} = \frac{- 27 \pm 9}{2 ( - 9 )}

Separate the solutions

x_{1} = \frac{- 27 + 9}{2 ( - 9 )}, x_{2} = \frac{- 27 - 9}{2 ( - 9 )}

x = \frac{- 27 + 9}{2 ( - 9 )} : 1

x = \frac{- 27 - 9}{2 ( - 9 )} : 2

The solutions to the quadratic equation are:

x = 1, x = 2

9 x^{2} + 21 x + 10 = 0

8 p^{2} + 6 p - 48 = 0

λ^{2} + 2 λ - 80 = 0

6 x^{2} - 5 x - 50 = 0

2 x^{2} - 6 x + 3 = 0

What are the solutions to the equation (x+4)^2=2x(5x-1)-17(x-2) ?
The solutions to the equation (x+4)^2=2x(5x-1)-17(x-2) are x=1,x=2
Find the zeros of (x+4)^2=2x(5x-1)-17(x-2)
The zeros of (x+4)^2=2x(5x-1)-17(x-2) are x=1,x=2