What are the solutions to the equation λ^2+2λ-80=0 ?

The solutions to the equation λ^2+2λ-80=0 are λ=8,λ=-10

Find the zeros of λ^2+2λ-80=0

The zeros of λ^2+2λ-80=0 are λ=8,λ=-10

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λ^{2} + 2 λ - 80 = 0

λ = 8, λ = - 10

Solution steps

λ^{2} + 2 λ - 80 = 0

Solve with the quadratic formula

λ_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 80 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 80) = 18

λ_{1, 2} = \frac{- 2 \pm 18}{2 \cdot 1}

Separate the solutions

λ_{1} = \frac{- 2 + 18}{2 \cdot 1}, λ_{2} = \frac{- 2 - 18}{2 \cdot 1}

λ = \frac{- 2 + 18}{2 \cdot 1} : 8

λ = \frac{- 2 - 18}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

λ = 8, λ = - 10

6 x^{2} - 5 x - 50 = 0

2 x^{2} - 6 x + 3 = 0

0.2 (2 x - 6) (8 x - 6) = 0

x, y + 5 x y = x^{2}

- (x - 3)^{2} + 2 = 0

What are the solutions to the equation λ^2+2λ-80=0 ?
The solutions to the equation λ^2+2λ-80=0 are λ=8,λ=-10
Find the zeros of λ^2+2λ-80=0
The zeros of λ^2+2λ-80=0 are λ=8,λ=-10