What are the solutions to the equation -(x-3)^2+2=0 ?

The solutions to the equation -(x-3)^2+2=0 are x=sqrt(2)+3,x=-sqrt(2)+3

Find the zeros of -(x-3)^2+2=0

The zeros of -(x-3)^2+2=0 are x=sqrt(2)+3,x=-sqrt(2)+3

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- (x - 3)^{2} + 2 = 0

x = 2 + 3, x = - 2 + 3

Decimal Notation

x = 4.41421 \dots, x = 1.58578 \dots

Solution steps

- (x - 3)^{2} + 2 = 0

Move

2

to the right side

- (x - 3)^{2} = - 2

Divide both sides by

- 1

(x - 3)^{2} = 2

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 2 : x = 2 + 3

Solve

x - 3 = - 2 : x = - 2 + 3

The solutions to the quadratic equation are:

x = 2 + 3, x = - 2 + 3

5 + x = 3 x^{2}

p^{2} - 3 p + 2 = 0

x^{2} - 960 x + 86000 = 0

x^{2} + 17 x - 22 = 0

x^{2} - 7 x = - 9

What are the solutions to the equation -(x-3)^2+2=0 ?
The solutions to the equation -(x-3)^2+2=0 are x=sqrt(2)+3,x=-sqrt(2)+3
Find the zeros of -(x-3)^2+2=0
The zeros of -(x-3)^2+2=0 are x=sqrt(2)+3,x=-sqrt(2)+3