What are the solutions to the equation x^2+17x-22=0 ?

The solutions to the equation x^2+17x-22=0 are x=(-17+sqrt(377))/2 ,x=(-17-sqrt(377))/2

Find the zeros of x^2+17x-22=0

The zeros of x^2+17x-22=0 are x=(-17+sqrt(377))/2 ,x=(-17-sqrt(377))/2

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x^{2} + 17 x - 22 = 0

x = \frac{- 17 + 377}{2}, x = \frac{- 17 - 377}{2}

Decimal Notation

x = 1.20824 \dots, x = - 18.20824 \dots

Solution steps

x^{2} + 17 x - 22 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 1 \cdot ( - 22 )}{2 \cdot 1}

1 7^{2} - 4 \cdot 1 \cdot (- 22) = 377

x_{1, 2} = \frac{- 17 \pm 377}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 17 + 377}{2 \cdot 1}, x_{2} = \frac{- 17 - 377}{2 \cdot 1}

x = \frac{- 17 + 377}{2 \cdot 1} : \frac{- 17 + 377}{2}

x = \frac{- 17 - 377}{2 \cdot 1} : \frac{- 17 - 377}{2}

The solutions to the quadratic equation are:

x = \frac{- 17 + 377}{2}, x = \frac{- 17 - 377}{2}

x^{2} - 7 x = - 9

x^{2} - 7 x = - 2

2 z^{2} + 8 z + 8 = 0

x, x^{2} - 9 x = 0

27 x^{2} + (- 18) x + 3 = 0

What are the solutions to the equation x^2+17x-22=0 ?
The solutions to the equation x^2+17x-22=0 are x=(-17+sqrt(377))/2 ,x=(-17-sqrt(377))/2
Find the zeros of x^2+17x-22=0
The zeros of x^2+17x-22=0 are x=(-17+sqrt(377))/2 ,x=(-17-sqrt(377))/2