What are the solutions to the equation 2z^2+8z+8=0 ?

The solutions to the equation 2z^2+8z+8=0 are z=-2

Find the zeros of 2z^2+8z+8=0

The zeros of 2z^2+8z+8=0 are z=-2

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2 z^{2} + 8 z + 8 = 0

z = - 2

Solution steps

2 z^{2} + 8 z + 8 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 \cdot 8}{2 \cdot 2}

8^{2} - 4 \cdot 2 \cdot 8 = 0

z_{1, 2} = \frac{- 8 \pm 0}{2 \cdot 2}

z = \frac{- 8}{2 \cdot 2}

\frac{- 8}{2 \cdot 2} = - 2

z = - 2

The solution to the quadratic equation is:

z = - 2

x, x^{2} - 9 x = 0

27 x^{2} + (- 18) x + 3 = 0

6 c^{2} - 14 c = 12

d, x = \frac{e ^{1.68} ( d ^{2} - 16.08 )}{24}

(3 x + 12)^{2} = 196

What are the solutions to the equation 2z^2+8z+8=0 ?
The solutions to the equation 2z^2+8z+8=0 are z=-2
Find the zeros of 2z^2+8z+8=0
The zeros of 2z^2+8z+8=0 are z=-2