What are the solutions to the equation 27x^2+(-18)x+3=0 ?

The solutions to the equation 27x^2+(-18)x+3=0 are x= 1/3

Find the zeros of 27x^2+(-18)x+3=0

The zeros of 27x^2+(-18)x+3=0 are x= 1/3

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27 x^{2} + (- 18) x + 3 = 0

x = \frac{1}{3}

Decimal Notation

x = 0.33333 \dots

Solution steps

27 x^{2} + (- 18) x + 3 = 0

Refine

27 x^{2} - 18 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 27 \cdot 3}{2 \cdot 27}

(- 18)^{2} - 4 \cdot 27 \cdot 3 = 0

x_{1, 2} = \frac{- ( - 18 ) \pm 0}{2 \cdot 27}

x = \frac{- ( - 18 )}{2 \cdot 27}

\frac{- ( - 18 )}{2 \cdot 27} = \frac{1}{3}

x = \frac{1}{3}

The solution to the quadratic equation is:

x = \frac{1}{3}

6 c^{2} - 14 c = 12

d, x = \frac{e ^{1.68} ( d ^{2} - 16.08 )}{24}

(3 x + 12)^{2} = 196

- 4 x^{2} + 84 = 4

- X^{2} + 7 X - 10 = 0

What are the solutions to the equation 27x^2+(-18)x+3=0 ?
The solutions to the equation 27x^2+(-18)x+3=0 are x= 1/3
Find the zeros of 27x^2+(-18)x+3=0
The zeros of 27x^2+(-18)x+3=0 are x= 1/3