What are the solutions to the equation 6c^2-14c=12 ?

The solutions to the equation 6c^2-14c=12 are c=3,c=-2/3

Find the zeros of 6c^2-14c=12

The zeros of 6c^2-14c=12 are c=3,c=-2/3

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6 c^{2} - 14 c = 12

c = 3, c = - \frac{2}{3}

Decimal Notation

c = 3, c = - 0.66666 \dots

Solution steps

6 c^{2} - 14 c = 12

Move

12

to the left side

6 c^{2} - 14 c - 12 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 6 ( - 12 )}{2 \cdot 6}

(- 14)^{2} - 4 \cdot 6 (- 12) = 22

c_{1, 2} = \frac{- ( - 14 ) \pm 22}{2 \cdot 6}

Separate the solutions

c_{1} = \frac{- ( - 14 ) + 22}{2 \cdot 6}, c_{2} = \frac{- ( - 14 ) - 22}{2 \cdot 6}

c = \frac{- ( - 14 ) + 22}{2 \cdot 6} : 3

c = \frac{- ( - 14 ) - 22}{2 \cdot 6} : - \frac{2}{3}

The solutions to the quadratic equation are:

c = 3, c = - \frac{2}{3}

d, x = \frac{e ^{1.68} ( d ^{2} - 16.08 )}{24}

(3 x + 12)^{2} = 196

- 4 x^{2} + 84 = 4

- X^{2} + 7 X - 10 = 0

x, - 12 x^{2} + 16 x = - 192

What are the solutions to the equation 6c^2-14c=12 ?
The solutions to the equation 6c^2-14c=12 are c=3,c=-2/3
Find the zeros of 6c^2-14c=12
The zeros of 6c^2-14c=12 are c=3,c=-2/3