What are the solutions to the equation -X^2+7X-10=0 ?

The solutions to the equation -X^2+7X-10=0 are X=2,X=5

Find the zeros of -X^2+7X-10=0

The zeros of -X^2+7X-10=0 are X=2,X=5

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- X^{2} + 7 X - 10 = 0

X = 2, X = 5

Solution steps

- X^{2} + 7 X - 10 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 1 ) ( - 10 )}{2 ( - 1 )}

7^{2} - 4 (- 1) (- 10) = 3

X_{1, 2} = \frac{- 7 \pm 3}{2 ( - 1 )}

Separate the solutions

X_{1} = \frac{- 7 + 3}{2 ( - 1 )}, X_{2} = \frac{- 7 - 3}{2 ( - 1 )}

X = \frac{- 7 + 3}{2 ( - 1 )} : 2

X = \frac{- 7 - 3}{2 ( - 1 )} : 5

The solutions to the quadratic equation are:

X = 2, X = 5

x, - 12 x^{2} + 16 x = - 192

t^{2} + 20 t = 0

p^{2} - 3 p + 5 = 0

a, (a + b + c) (a + b - c) = 3 ab

(x + 1) (x + 6) = 0

What are the solutions to the equation -X^2+7X-10=0 ?
The solutions to the equation -X^2+7X-10=0 are X=2,X=5
Find the zeros of -X^2+7X-10=0
The zeros of -X^2+7X-10=0 are X=2,X=5