What are the solutions to the equation 25x^2+100x+100=0 ?

The solutions to the equation 25x^2+100x+100=0 are x=-2

Find the zeros of 25x^2+100x+100=0

The zeros of 25x^2+100x+100=0 are x=-2

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25 x^{2} + 100 x + 100 = 0

x = - 2

Solution steps

25 x^{2} + 100 x + 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 100 \pm 10 0 ^{2} - 4 \cdot 25 \cdot 100}{2 \cdot 25}

10 0^{2} - 4 \cdot 25 \cdot 100 = 0

x_{1, 2} = \frac{- 100 \pm 0}{2 \cdot 25}

x = \frac{- 100}{2 \cdot 25}

\frac{- 100}{2 \cdot 25} = - 2

x = - 2

The solution to the quadratic equation is:

x = - 2

x^{2} - 65 x + 950 = 0

2 x^{1} + 8 x^{2} = 10

x^{2} + 9 x + 25 = 0

5 x^{2} - 38 = 187

2 x^{2} + b x = 3

What are the solutions to the equation 25x^2+100x+100=0 ?
The solutions to the equation 25x^2+100x+100=0 are x=-2
Find the zeros of 25x^2+100x+100=0
The zeros of 25x^2+100x+100=0 are x=-2