What are the solutions to the equation x^2-16x+64=-8 ?

The solutions to the equation x^2-16x+64=-8 are x=8+2sqrt(2)i,x=8-2sqrt(2)i

Find the zeros of x^2-16x+64=-8

The zeros of x^2-16x+64=-8 are x=8+2sqrt(2)i,x=8-2sqrt(2)i

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x^{2} - 16 x + 64 = - 8

x = 8 + 22 i, x = 8 - 22 i

Solution steps

x^{2} - 16 x + 64 = - 8

Move

8

to the left side

x^{2} - 16 x + 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 72}{2 \cdot 1}

Simplify

(- 16)^{2} - 4 \cdot 1 \cdot 72 : 42 i

x_{1, 2} = \frac{- ( - 16 ) \pm 4 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 4 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 4 2 i}{2 \cdot 1}

x = \frac{- ( - 16 ) + 4 2 i}{2 \cdot 1} : 8 + 22 i

x = \frac{- ( - 16 ) - 4 2 i}{2 \cdot 1} : 8 - 22 i

The solutions to the quadratic equation are:

x = 8 + 22 i, x = 8 - 22 i

14 x^{2} - 3 x = 0

\frac{2}{3} x \frac{5}{7} x \frac{a}{2} = \frac{60}{42}

v^{2} = - 18 - 10 v

s^{2} + 6 s + 6 = 0

\frac{1}{4} (2 x - 7) (2 x - 1)

What are the solutions to the equation x^2-16x+64=-8 ?
The solutions to the equation x^2-16x+64=-8 are x=8+2sqrt(2)i,x=8-2sqrt(2)i
Find the zeros of x^2-16x+64=-8
The zeros of x^2-16x+64=-8 are x=8+2sqrt(2)i,x=8-2sqrt(2)i