What are the solutions to the equation s^2+6s+6=0 ?

The solutions to the equation s^2+6s+6=0 are s=-3+sqrt(3),s=-3-sqrt(3)

Find the zeros of s^2+6s+6=0

The zeros of s^2+6s+6=0 are s=-3+sqrt(3),s=-3-sqrt(3)

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s^{2} + 6 s + 6 = 0

s = - 3 + 3, s = - 3 - 3

Decimal Notation

s = - 1.26794 \dots, s = - 4.73205 \dots

Solution steps

s^{2} + 6 s + 6 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 6 = 23

s_{1, 2} = \frac{- 6 \pm 2 3}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 6 + 2 3}{2 \cdot 1}, s_{2} = \frac{- 6 - 2 3}{2 \cdot 1}

s = \frac{- 6 + 2 3}{2 \cdot 1} : - 3 + 3

s = \frac{- 6 - 2 3}{2 \cdot 1} : - 3 - 3

The solutions to the quadratic equation are:

s = - 3 + 3, s = - 3 - 3

\frac{1}{4} (2 x - 7) (2 x - 1)

lo g_{10} (5) (x^{2} - 6 x - 7) - lo g_{10} (5) (x + 1) = 1

- 3 x^{2} + 10 x - 8

- 2 x^{2} + x - 1

X^{2} + 2 X = 0

What are the solutions to the equation s^2+6s+6=0 ?
The solutions to the equation s^2+6s+6=0 are s=-3+sqrt(3),s=-3-sqrt(3)
Find the zeros of s^2+6s+6=0
The zeros of s^2+6s+6=0 are s=-3+sqrt(3),s=-3-sqrt(3)