What are the solutions to the equation completesquare-3x^2+10x-8 ?

The solutions to the equation completesquare-3x^2+10x-8 are -3(x-5/3)^2+1/3

Find the zeros of completesquare-3x^2+10x-8

The zeros of completesquare-3x^2+10x-8 are -3(x-5/3)^2+1/3

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complete the square

- 3 x^{2} + 10 x - 8

- 3 (x - \frac{5}{3})^{2} + \frac{1}{3}

Solution steps

- 3 x^{2} + 10 x - 8

Write

- 3 x^{2} + 10 x - 8

in the form:

x^{2} + 2 a x + a^{2}

Factor out

- 3

- 3 (x^{2} - \frac{10 x}{3} + \frac{8}{3})

2 a = - \frac{10}{3} : a = - \frac{5}{3}

Add and subtract

(- \frac{5}{3})^{2}

- 3 (x^{2} - \frac{10 x}{3} + \frac{8}{3} + (- \frac{5}{3})^{2} - (- \frac{5}{3})^{2})

x^{2} + 2 a x + a^{2} = (x + a)^{2}

x^{2} - \frac{10}{3} x + (- \frac{5}{3})^{2} = (x - \frac{5}{3})^{2}

- 3 ((x - \frac{5}{3})^{2} + \frac{8}{3} - (- \frac{5}{3})^{2})

Simplify

- 3 (x - \frac{5}{3})^{2} + \frac{1}{3}

- 2 x^{2} + x - 1

X^{2} + 2 X = 0

- 7 + 16 k^{2} = 9

(x + 2) (x - 4) = 27

2 x^{2} + 3 x - 1

What are the solutions to the equation completesquare-3x^2+10x-8 ?
The solutions to the equation completesquare-3x^2+10x-8 are -3(x-5/3)^2+1/3
Find the zeros of completesquare-3x^2+10x-8
The zeros of completesquare-3x^2+10x-8 are -3(x-5/3)^2+1/3