What are the solutions to the equation X^2+2X=0 ?

The solutions to the equation X^2+2X=0 are X=0,X=-2

Find the zeros of X^2+2X=0

The zeros of X^2+2X=0 are X=0,X=-2

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X^{2} + 2 X = 0

X = 0, X = - 2

Solution steps

X^{2} + 2 X = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot 0 = 2

X_{1, 2} = \frac{- 2 \pm 2}{2 \cdot 1}

Separate the solutions

X_{1} = \frac{- 2 + 2}{2 \cdot 1}, X_{2} = \frac{- 2 - 2}{2 \cdot 1}

X = \frac{- 2 + 2}{2 \cdot 1} : 0

X = \frac{- 2 - 2}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

X = 0, X = - 2

- 7 + 16 k^{2} = 9

(x + 2) (x - 4) = 27

2 x^{2} + 3 x - 1

x^{2} + 3 x + 2 = 1

9 f^{2} + 6 f + 1 = 0

What are the solutions to the equation X^2+2X=0 ?
The solutions to the equation X^2+2X=0 are X=0,X=-2
Find the zeros of X^2+2X=0
The zeros of X^2+2X=0 are X=0,X=-2