What are the solutions to the equation 9f^2+6f+1=0 ?

The solutions to the equation 9f^2+6f+1=0 are f=-1/3

Find the zeros of 9f^2+6f+1=0

The zeros of 9f^2+6f+1=0 are f=-1/3

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9 f^{2} + 6 f + 1 = 0

f = - \frac{1}{3}

Decimal Notation

f = - 0.33333 \dots

Solution steps

9 f^{2} + 6 f + 1 = 0

Solve with the quadratic formula

f_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 9 \cdot 1}{2 \cdot 9}

6^{2} - 4 \cdot 9 \cdot 1 = 0

f_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 9}

f = \frac{- 6}{2 \cdot 9}

\frac{- 6}{2 \cdot 9} = - \frac{1}{3}

f = - \frac{1}{3}

The solution to the quadratic equation is:

f = - \frac{1}{3}

2 x^{2} - 2 = - 18

0.0138 x + \frac{( - 9.47 \cdot 1 0 ^{- 4} )}{2} x^{2} = 0.0111 x + \frac{( 15.15 \cdot 1 0 ^{- 4} )}{2} x^{2}

12 - 36 x + 18 x^{2} = 0

9 (2 x^{2} + 2) - 2 = 3 (4 x^{2} - 2) - 3 x^{2} - 2 x

3 t^{2} - 18 t = 0

What are the solutions to the equation 9f^2+6f+1=0 ?
The solutions to the equation 9f^2+6f+1=0 are f=-1/3
Find the zeros of 9f^2+6f+1=0
The zeros of 9f^2+6f+1=0 are f=-1/3