What are the solutions to the equation 3x-x^2=x ?

The solutions to the equation 3x-x^2=x are x=0,x=2

Find the zeros of 3x-x^2=x

The zeros of 3x-x^2=x are x=0,x=2

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3 x - x^{2} = x

x = 0, x = 2

Solution steps

3 x - x^{2} = x

Move

x

to the left side

- x^{2} + 2 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

2^{2} - 4 (- 1) \cdot 0 = 2

x_{1, 2} = \frac{- 2 \pm 2}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 2 + 2}{2 ( - 1 )}, x_{2} = \frac{- 2 - 2}{2 ( - 1 )}

x = \frac{- 2 + 2}{2 ( - 1 )} : 0

x = \frac{- 2 - 2}{2 ( - 1 )} : 2

The solutions to the quadratic equation are:

x = 0, x = 2

a, (a + b + c)^{2} = 144

2 w^{2} + 3 w - 35 = 0

0 = - 12 x^{2} + 4

x, 2 x^{2} + 3 y^{2} + x + 4 y + 5 = 0

11 x = 2 x^{2} + 12

What are the solutions to the equation 3x-x^2=x ?
The solutions to the equation 3x-x^2=x are x=0,x=2
Find the zeros of 3x-x^2=x
The zeros of 3x-x^2=x are x=0,x=2