What are the solutions to the equation 0=-x^2-12x-36 ?

The solutions to the equation 0=-x^2-12x-36 are x=-6

Find the zeros of 0=-x^2-12x-36

The zeros of 0=-x^2-12x-36 are x=-6

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0 = - x^{2} - 12 x - 36

x = - 6

Solution steps

0 = - x^{2} - 12 x - 36

Switch sides

- x^{2} - 12 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 ( - 1 ) ( - 36 )}{2 ( - 1 )}

(- 12)^{2} - 4 (- 1) (- 36) = 0

x_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 ( - 1 )}

x = \frac{- ( - 12 )}{2 ( - 1 )}

\frac{- ( - 12 )}{2 ( - 1 )} = - 6

x = - 6

The solution to the quadratic equation is:

x = - 6

z^{2} + 15 = 6

(y - 3)^{2} = - 10 (y + 3)

x^{2} + 2 x - 360 = 0

x, x^{2} + y^{3} = 4

x, x^{2} + 4 x = 1

What are the solutions to the equation 0=-x^2-12x-36 ?
The solutions to the equation 0=-x^2-12x-36 are x=-6
Find the zeros of 0=-x^2-12x-36
The zeros of 0=-x^2-12x-36 are x=-6