What are the solutions to the equation solvefor x,x^2+y^3=4 ?

The solutions to the equation solvefor x,x^2+y^3=4 are x=sqrt(4-y^3),x=-sqrt(4-y^3)

Find the zeros of solvefor x,x^2+y^3=4

The zeros of solvefor x,x^2+y^3=4 are x=sqrt(4-y^3),x=-sqrt(4-y^3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solve for

x, x^{2} + y^{3} = 4

x = 4 - y^{3}, x = - 4 - y^{3}

Solution steps

x^{2} + y^{3} = 4

Move

y^{3}

to the right side

x^{2} = 4 - y^{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4 - y^{3}, x = - 4 - y^{3}

x, x^{2} + 4 x = 1

t^{2} - 14 t + 49 = 0

4 x^{2} - 5 = 31

n^{2} - 18 n = - 73

x^{2} - 10 x - 13 = 0

What are the solutions to the equation solvefor x,x^2+y^3=4 ?
The solutions to the equation solvefor x,x^2+y^3=4 are x=sqrt(4-y^3),x=-sqrt(4-y^3)
Find the zeros of solvefor x,x^2+y^3=4
The zeros of solvefor x,x^2+y^3=4 are x=sqrt(4-y^3),x=-sqrt(4-y^3)