What are the solutions to the equation n^2-18n=-73 ?

The solutions to the equation n^2-18n=-73 are n=9+2sqrt(2),n=9-2sqrt(2)

Find the zeros of n^2-18n=-73

The zeros of n^2-18n=-73 are n=9+2sqrt(2),n=9-2sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

n^{2} - 18 n = - 73

n = 9 + 22, n = 9 - 22

Decimal Notation

n = 11.82842 \dots, n = 6.17157 \dots

Solution steps

n^{2} - 18 n = - 73

Move

73

to the left side

n^{2} - 18 n + 73 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 73}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot 73 = 42

n_{1, 2} = \frac{- ( - 18 ) \pm 4 2}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 18 ) + 4 2}{2 \cdot 1}, n_{2} = \frac{- ( - 18 ) - 4 2}{2 \cdot 1}

n = \frac{- ( - 18 ) + 4 2}{2 \cdot 1} : 9 + 22

n = \frac{- ( - 18 ) - 4 2}{2 \cdot 1} : 9 - 22

The solutions to the quadratic equation are:

n = 9 + 22, n = 9 - 22

x^{2} - 10 x - 13 = 0

- 3 x^{2} + 11 x + 9 = 1

5.56 \cdot 1 0^{- 10} = \frac{x ^{2}}{2.5}

x^{2} - 1 = - 2 x

x, x^{2} = \frac{1}{y ^{3}}

What are the solutions to the equation n^2-18n=-73 ?
The solutions to the equation n^2-18n=-73 are n=9+2sqrt(2),n=9-2sqrt(2)
Find the zeros of n^2-18n=-73
The zeros of n^2-18n=-73 are n=9+2sqrt(2),n=9-2sqrt(2)