What are the solutions to the equation x^2-1=-2x ?

The solutions to the equation x^2-1=-2x are x=-1+sqrt(2),x=-1-sqrt(2)

Find the zeros of x^2-1=-2x

The zeros of x^2-1=-2x are x=-1+sqrt(2),x=-1-sqrt(2)

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x^{2} - 1 = - 2 x

x = - 1 + 2, x = - 1 - 2

Decimal Notation

x = 0.41421 \dots, x = - 2.41421 \dots

Solution steps

x^{2} - 1 = - 2 x

Move

2 x

to the left side

x^{2} - 1 + 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 1) = 22

x_{1, 2} = \frac{- 2 \pm 2 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 2}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 2}{2 \cdot 1}

x = \frac{- 2 + 2 2}{2 \cdot 1} : - 1 + 2

x = \frac{- 2 - 2 2}{2 \cdot 1} : - 1 - 2

The solutions to the quadratic equation are:

x = - 1 + 2, x = - 1 - 2

x, x^{2} = \frac{1}{y ^{3}}

(x + 1)^{2} = x + 1

0.2 x^{2} - 1.5 x + 2.9 = 0

x^{2} - 10 x + 19 = 3

x, I n (- x) = I n (x^{2} - 6)

What are the solutions to the equation x^2-1=-2x ?
The solutions to the equation x^2-1=-2x are x=-1+sqrt(2),x=-1-sqrt(2)
Find the zeros of x^2-1=-2x
The zeros of x^2-1=-2x are x=-1+sqrt(2),x=-1-sqrt(2)