What are the solutions to the equation 12x^2-68x+72=0 ?

The solutions to the equation 12x^2-68x+72=0 are x=(17+sqrt(73))/6 ,x=(17-sqrt(73))/6

Find the zeros of 12x^2-68x+72=0

The zeros of 12x^2-68x+72=0 are x=(17+sqrt(73))/6 ,x=(17-sqrt(73))/6

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12 x^{2} - 68 x + 72 = 0

x = \frac{17 + 73}{6}, x = \frac{17 - 73}{6}

Decimal Notation

x = 4.25733 \dots, x = 1.40933 \dots

Solution steps

12 x^{2} - 68 x + 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 68 ) \pm ( - 68 ) ^{2} - 4 \cdot 12 \cdot 72}{2 \cdot 12}

(- 68)^{2} - 4 \cdot 12 \cdot 72 = 473

x_{1, 2} = \frac{- ( - 68 ) \pm 4 73}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 68 ) + 4 73}{2 \cdot 12}, x_{2} = \frac{- ( - 68 ) - 4 73}{2 \cdot 12}

x = \frac{- ( - 68 ) + 4 73}{2 \cdot 12} : \frac{17 + 73}{6}

x = \frac{- ( - 68 ) - 4 73}{2 \cdot 12} : \frac{17 - 73}{6}

The solutions to the quadratic equation are:

x = \frac{17 + 73}{6}, x = \frac{17 - 73}{6}

12 x^{2} - 104 x + 168 = 0

- 36 x^{2} = 0

p^{2} = 40

- 5 x^{2} + 7 x + 9 = 0

(x + 6) (x - 2) = 0

What are the solutions to the equation 12x^2-68x+72=0 ?
The solutions to the equation 12x^2-68x+72=0 are x=(17+sqrt(73))/6 ,x=(17-sqrt(73))/6
Find the zeros of 12x^2-68x+72=0
The zeros of 12x^2-68x+72=0 are x=(17+sqrt(73))/6 ,x=(17-sqrt(73))/6