What are the solutions to the equation (x+4)^2-81=0 ?

The solutions to the equation (x+4)^2-81=0 are x=5,x=-13

Find the zeros of (x+4)^2-81=0

The zeros of (x+4)^2-81=0 are x=5,x=-13

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(x + 4)^{2} - 81 = 0

x = 5, x = - 13

Solution steps

(x + 4)^{2} - 81 = 0

Move

81

to the right side

(x + 4)^{2} = 81

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = 81 : x = 5

Solve

x + 4 = - 81 : x = - 13

The solutions to the quadratic equation are:

x = 5, x = - 13

- 2 x + 5 = x^{2} - 3 x - 85

x^{2} + 16 x + 17 = 0

(14 - m) x^{2} + (7 + m) x + (m - 2) = 0

300 = (75 x - 0.5 x^{2}) - (35 x + 300)

3 x^{2} - 8 = 4

What are the solutions to the equation (x+4)^2-81=0 ?
The solutions to the equation (x+4)^2-81=0 are x=5,x=-13
Find the zeros of (x+4)^2-81=0
The zeros of (x+4)^2-81=0 are x=5,x=-13