What are the solutions to the equation 7x^2+2=7x ?

The solutions to the equation 7x^2+2=7x are x= 1/2+i(sqrt(7))/(14),x= 1/2-i(sqrt(7))/(14)

Find the zeros of 7x^2+2=7x

The zeros of 7x^2+2=7x are x= 1/2+i(sqrt(7))/(14),x= 1/2-i(sqrt(7))/(14)

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7 x^{2} + 2 = 7 x

x = \frac{1}{2} + i \frac{7}{14}, x = \frac{1}{2} - i \frac{7}{14}

Solution steps

7 x^{2} + 2 = 7 x

Move

7 x

to the left side

7 x^{2} + 2 - 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

7 x^{2} - 7 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 7 \cdot 2}{2 \cdot 7}

Simplify

(- 7)^{2} - 4 \cdot 7 \cdot 2 : 7 i

x_{1, 2} = \frac{- ( - 7 ) \pm 7 i}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 7 i}{2 \cdot 7}, x_{2} = \frac{- ( - 7 ) - 7 i}{2 \cdot 7}

x = \frac{- ( - 7 ) + 7 i}{2 \cdot 7} : \frac{1}{2} + i \frac{7}{14}

x = \frac{- ( - 7 ) - 7 i}{2 \cdot 7} : \frac{1}{2} - i \frac{7}{14}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{7}{14}, x = \frac{1}{2} - i \frac{7}{14}

x^{2} - 6 x - 9 = 0

4 k (k + 6) = 6

x^{2} - 2 x = - 8 x

120 - q^{2} = 32 + 3 q

x^{2} - 2 x = - 63

What are the solutions to the equation 7x^2+2=7x ?
The solutions to the equation 7x^2+2=7x are x= 1/2+i(sqrt(7))/(14),x= 1/2-i(sqrt(7))/(14)
Find the zeros of 7x^2+2=7x
The zeros of 7x^2+2=7x are x= 1/2+i(sqrt(7))/(14),x= 1/2-i(sqrt(7))/(14)