What are the solutions to the equation 2x^2-6x+17=0 ?

The solutions to the equation 2x^2-6x+17=0 are x= 3/2+i 5/2 ,x= 3/2-i 5/2

Find the zeros of 2x^2-6x+17=0

The zeros of 2x^2-6x+17=0 are x= 3/2+i 5/2 ,x= 3/2-i 5/2

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2 x^{2} - 6 x + 17 = 0

x = \frac{3}{2} + i \frac{5}{2}, x = \frac{3}{2} - i \frac{5}{2}

Solution steps

2 x^{2} - 6 x + 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 2 \cdot 17}{2 \cdot 2}

Simplify

(- 6)^{2} - 4 \cdot 2 \cdot 17 : 10 i

x_{1, 2} = \frac{- ( - 6 ) \pm 10 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 10 i}{2 \cdot 2}, x_{2} = \frac{- ( - 6 ) - 10 i}{2 \cdot 2}

x = \frac{- ( - 6 ) + 10 i}{2 \cdot 2} : \frac{3}{2} + i \frac{5}{2}

x = \frac{- ( - 6 ) - 10 i}{2 \cdot 2} : \frac{3}{2} - i \frac{5}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2} + i \frac{5}{2}, x = \frac{3}{2} - i \frac{5}{2}

30 x^{2} = 0

x^{2} + 4 x = 7 x

2 x (x - 3) = 9

- 3 x^{1} + 5 x^{2} = 45

X^{2} + 2 = 0

What are the solutions to the equation 2x^2-6x+17=0 ?
The solutions to the equation 2x^2-6x+17=0 are x= 3/2+i 5/2 ,x= 3/2-i 5/2
Find the zeros of 2x^2-6x+17=0
The zeros of 2x^2-6x+17=0 are x= 3/2+i 5/2 ,x= 3/2-i 5/2