What are the solutions to the equation -3x^1+5x^2=45 ?

The solutions to the equation -3x^1+5x^2=45 are x=(3+3sqrt(101))/(10),x=(3-3sqrt(101))/(10)

Find the zeros of -3x^1+5x^2=45

The zeros of -3x^1+5x^2=45 are x=(3+3sqrt(101))/(10),x=(3-3sqrt(101))/(10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 3 x^{1} + 5 x^{2} = 45

x = \frac{3 + 3 101}{10}, x = \frac{3 - 3 101}{10}

Decimal Notation

x = 3.31496 \dots, x = - 2.71496 \dots

Solution steps

- 3 x^{1} + 5 x^{2} = 45

Refine

- 3 x + 5 x^{2} = 45

Move

45

to the left side

- 3 x + 5 x^{2} - 45 = 0

Write in the standard form

a x^{2} + b x + c = 0

5 x^{2} - 3 x - 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 5 ( - 45 )}{2 \cdot 5}

(- 3)^{2} - 4 \cdot 5 (- 45) = 3101

x_{1, 2} = \frac{- ( - 3 ) \pm 3 101}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3 101}{2 \cdot 5}, x_{2} = \frac{- ( - 3 ) - 3 101}{2 \cdot 5}

x = \frac{- ( - 3 ) + 3 101}{2 \cdot 5} : \frac{3 + 3 101}{10}

x = \frac{- ( - 3 ) - 3 101}{2 \cdot 5} : \frac{3 - 3 101}{10}

The solutions to the quadratic equation are:

x = \frac{3 + 3 101}{10}, x = \frac{3 - 3 101}{10}

X^{2} + 2 = 0

(x + 2)^{2} + 9 = 0

x^{2} + x - 17 = 0

x^{2} + 4.37 x - 21.28 = 0

(2 x - 1)^{2} + 5 = - 23

What are the solutions to the equation -3x^1+5x^2=45 ?
The solutions to the equation -3x^1+5x^2=45 are x=(3+3sqrt(101))/(10),x=(3-3sqrt(101))/(10)
Find the zeros of -3x^1+5x^2=45
The zeros of -3x^1+5x^2=45 are x=(3+3sqrt(101))/(10),x=(3-3sqrt(101))/(10)