What are the solutions to the equation x^2+10=25 ?

The solutions to the equation x^2+10=25 are x=sqrt(15),x=-sqrt(15)

Find the zeros of x^2+10=25

The zeros of x^2+10=25 are x=sqrt(15),x=-sqrt(15)

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x^{2} + 10 = 25

x = 15, x = - 15

Decimal Notation

x = 3.87298 \dots, x = - 3.87298 \dots

Solution steps

x^{2} + 10 = 25

Move

10

to the right side

x^{2} = 15

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 15, x = - 15

x, x^{2} + (\frac{4 x}{3})^{2} = 225

0 = x^{2} - 12 x

1 3^{2} + 1 2^{2} = c^{2}

(3 x + 1) (x - 4) = (2 x + 1) (x - 1) - 37

7 x^{2} - 567 = 0

What are the solutions to the equation x^2+10=25 ?
The solutions to the equation x^2+10=25 are x=sqrt(15),x=-sqrt(15)
Find the zeros of x^2+10=25
The zeros of x^2+10=25 are x=sqrt(15),x=-sqrt(15)