What are the solutions to the equation 0=x^2-12x ?

The solutions to the equation 0=x^2-12x are x=12,x=0

Find the zeros of 0=x^2-12x

The zeros of 0=x^2-12x are x=12,x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = x^{2} - 12 x

x = 12, x = 0

Solution steps

0 = x^{2} - 12 x

Switch sides

x^{2} - 12 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 0 = 12

x_{1, 2} = \frac{- ( - 12 ) \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 12}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 12}{2 \cdot 1}

x = \frac{- ( - 12 ) + 12}{2 \cdot 1} : 12

x = \frac{- ( - 12 ) - 12}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 12, x = 0

1 3^{2} + 1 2^{2} = c^{2}

(3 x + 1) (x - 4) = (2 x + 1) (x - 1) - 37

7 x^{2} - 567 = 0

- x^{2} - 2 + 3 = 0

x^{2} - 9 x - 26 = 0

What are the solutions to the equation 0=x^2-12x ?
The solutions to the equation 0=x^2-12x are x=12,x=0
Find the zeros of 0=x^2-12x
The zeros of 0=x^2-12x are x=12,x=0