What are the solutions to the equation -x^2-2+3=0 ?

The solutions to the equation -x^2-2+3=0 are x=1,x=-1

Find the zeros of -x^2-2+3=0

The zeros of -x^2-2+3=0 are x=1,x=-1

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- x^{2} - 2 + 3 = 0

x = 1, x = - 1

Solution steps

- x^{2} - 2 + 3 = 0

Move

2

to the right side

- x^{2} + 3 = 2

Move

3

to the right side

- x^{2} = - 1

Divide both sides by

- 1

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

x^{2} - 9 x - 26 = 0

y, - x^{2} y^{2} = k

x^{2} + 14 x - 15 = 0

w, 125 = w^{2} h

4 x^{2} - 18 x + 414 = - 2 x^{2} + 84 x + 162

What are the solutions to the equation -x^2-2+3=0 ?
The solutions to the equation -x^2-2+3=0 are x=1,x=-1
Find the zeros of -x^2-2+3=0
The zeros of -x^2-2+3=0 are x=1,x=-1