What are the solutions to the equation solvefor y,-x^2y^2=k ?

The solutions to the equation solvefor y,-x^2y^2=k are y=(isqrt(k))/x ,y=-(isqrt(k))/x ;\quad x\ne 0

Find the zeros of solvefor y,-x^2y^2=k

The zeros of solvefor y,-x^2y^2=k are y=(isqrt(k))/x ,y=-(isqrt(k))/x ;\quad x\ne 0

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solve for

y, - x^{2} y^{2} = k

y = \frac{i k}{x}, y = - \frac{i k}{x}; x \neq = 0

Solution steps

- x^{2} y^{2} = k

Divide both sides by

- x^{2}; x \neq = 0

y^{2} = - \frac{k}{x ^{2}}; x \neq = 0

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = - \frac{k}{x ^{2}}, y = - - \frac{k}{x ^{2}}; x \neq = 0

Simplify

- \frac{k}{x ^{2}} : \frac{i k}{x}

Simplify

- - \frac{k}{x ^{2}} : - \frac{i k}{x}

y = \frac{i k}{x}, y = - \frac{i k}{x}; x \neq = 0

x^{2} + 14 x - 15 = 0

w, 125 = w^{2} h

4 x^{2} - 18 x + 414 = - 2 x^{2} + 84 x + 162

2 x^{2} - 8 x = 16

x^{2} = 3^{2} + 8^{2}

What are the solutions to the equation solvefor y,-x^2y^2=k ?
The solutions to the equation solvefor y,-x^2y^2=k are y=(isqrt(k))/x ,y=-(isqrt(k))/x ;\quad x\ne 0
Find the zeros of solvefor y,-x^2y^2=k
The zeros of solvefor y,-x^2y^2=k are y=(isqrt(k))/x ,y=-(isqrt(k))/x ;\quad x\ne 0